common/bit_field: Make BitField trivially copyable
This makes the class much more flexible and doesn't make performing copies with classes that contain a bitfield member a pain. Given BitField instances are only intended to be used within unions, the fact the full storage value would be copied isn't a big concern (only sizeof(union_type) would be copied anyways). While we're at it, provide defaulted move constructors for consistency.
This commit is contained in:
parent
3b63a46ca4
commit
e99a148628
|
@ -111,12 +111,6 @@
|
|||
template <std::size_t Position, std::size_t Bits, typename T>
|
||||
struct BitField {
|
||||
private:
|
||||
// We hide the copy assigment operator here, because the default copy
|
||||
// assignment would copy the full storage value, rather than just the bits
|
||||
// relevant to this particular bit field.
|
||||
// We don't delete it because we want BitField to be trivially copyable.
|
||||
constexpr BitField& operator=(const BitField&) = default;
|
||||
|
||||
// UnderlyingType is T for non-enum types and the underlying type of T if
|
||||
// T is an enumeration. Note that T is wrapped within an enable_if in the
|
||||
// former case to workaround compile errors which arise when using
|
||||
|
@ -163,9 +157,13 @@ public:
|
|||
BitField(T val) = delete;
|
||||
BitField& operator=(T val) = delete;
|
||||
|
||||
// Force default constructor to be created
|
||||
// so that we can use this within unions
|
||||
constexpr BitField() = default;
|
||||
constexpr BitField() noexcept = default;
|
||||
|
||||
constexpr BitField(const BitField&) noexcept = default;
|
||||
constexpr BitField& operator=(const BitField&) noexcept = default;
|
||||
|
||||
constexpr BitField(BitField&&) noexcept = default;
|
||||
constexpr BitField& operator=(BitField&&) noexcept = default;
|
||||
|
||||
constexpr FORCE_INLINE operator T() const {
|
||||
return Value();
|
||||
|
|
Reference in New Issue