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Common: Simplify and optimize BitSet iterator

Instead of doing complex machinations to keep track of the current bit
index, just unset the lowest bit on each iteration, greatly simplifying
the code.
This commit is contained in:
Yuri Kunde Schlesner 2017-12-09 20:16:07 -08:00
parent 176ed77506
commit a5aa5e2b2d
1 changed files with 6 additions and 21 deletions

View File

@ -120,20 +120,15 @@ public:
// A STL-like iterator is required to be able to use range-based for loops.
class Iterator {
public:
Iterator(const Iterator& other) : m_val(other.m_val), m_bit(other.m_bit) {}
Iterator(IntTy val) : m_val(val), m_bit(0) {}
Iterator& operator=(Iterator other) {
new (this) Iterator(other);
return *this;
}
Iterator(const Iterator& other) : m_val(other.m_val) {}
Iterator(IntTy val) : m_val(val) {}
int operator*() {
return m_bit + ComputeLsb();
// This will never be called when m_val == 0, because that would be the end() iterator
return LeastSignificantSetBit(m_val);
}
Iterator& operator++() {
int lsb = ComputeLsb();
m_val >>= lsb + 1;
m_bit += lsb + 1;
m_has_lsb = false;
// Unset least significant set bit
m_val &= m_val - IntTy(1);
return *this;
}
Iterator operator++(int _) {
@ -149,17 +144,7 @@ public:
}
private:
int ComputeLsb() {
if (!m_has_lsb) {
m_lsb = LeastSignificantSetBit(m_val);
m_has_lsb = true;
}
return m_lsb;
}
IntTy m_val;
int m_bit;
int m_lsb = -1;
bool m_has_lsb = false;
};
BitSet() : m_val(0) {}