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Make bitfield assignment operator public

This change needs to be made to get the code compiling again. It was suggested after a conversation with Lioncash.

The conversation can be seen here: https://user-images.githubusercontent.com/20753089/45064197-b6107800-b0b2-11e8-9db8-f696299fb86a.PNG
This commit is contained in:
fearlessTobi 2018-09-05 02:24:44 +02:00
parent 89abef3518
commit efd83570bd
1 changed files with 2 additions and 6 deletions

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@ -112,12 +112,6 @@
template <std::size_t Position, std::size_t Bits, typename T, typename EndianTag = LETag>
struct BitField {
private:
// We hide the copy assigment operator here, because the default copy
// assignment would copy the full storage value, rather than just the bits
// relevant to this particular bit field.
// We don't delete it because we want BitField to be trivially copyable.
constexpr BitField& operator=(const BitField&) = default;
// UnderlyingType is T for non-enum types and the underlying type of T if
// T is an enumeration. Note that T is wrapped within an enable_if in the
// former case to workaround compile errors which arise when using
@ -131,6 +125,8 @@ private:
using StorageTypeWithEndian = typename AddEndian<StorageType, EndianTag>::type;
public:
BitField& operator=(const BitField&) = default;
/// Constants to allow limited introspection of fields if needed
static constexpr std::size_t position = Position;
static constexpr std::size_t bits = Bits;